1158 Sum of Consecutive Odd Numbers III

URI Online Judge | 1158

Sum of Consecutive Odd Numbers III

Read an integer N that is the number of test cases that follows. Each test case contains two integers X and Y. Print one output line for each test case that is the sum of Y odd numbers from X including it if is the case. For example:
for the input 4 5, the output must be 45, that is: 5 + 7 + 9 + 11 + 13
for the input 7 4, the output must be 40, that is: 7 + 9 + 11 + 13

Input

The first line of the input is an integer N that is the number of test cases that follow. Each test case is a line containing two integer X and Y.

Output

Print the sum of all consecutive odd numbers from X.

Input Sample	Output Sample
2 4 3 11 2	21 24

Solution:

#include<stdio.h> int main() {     int n,i=1,j,X,Y,sum;     scanf("%d",&n);     for(i = 0;i < n;i++){         sum = 0;         scanf("%d %d",&X,&Y);         if(X%2==0)             X++;         for(j = 0;j < Y;j++){             sum += X;             X += 2;;         }         printf("%d\n",sum);     }     return 0; }