1172 Array Replacement I

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Array Replacement I

Read an array X[10]. After, replace every null or negative number of X ​by 1. Print all numbers stored in the array X.

Input

The input contains 10 integer numbers. These numbers ​​can be positive or negative.

Output

For each position of the array, print "X [i] = x", where i is the position of the array and x is the number stored in that position.

Input Sample	Output Sample
0 -5 63 0 ...	X[0] = 1 X[1] = 1 X[2] = 63 X[3] = 1 ...

Solution:

#include <stdio.h> int main() {     int ar[10],i;     for(i=0; i<10; i++)         scanf("%d",&ar[i]);     for(i=0; i<10; i++)     {         if(ar[i]<=0)             ar[i]=1;     }     for(i=0; i<10; i++)         printf("X[%d] = %d\n",i,ar[i]);     return 0; }